x^2+0,2x+0,010,x=0,9

Solution for x^2+0,2x+0,010,x=0,9 equation:

x^2+0.2x+0.010.x=0.9

We move all terms to the left:

x^2+0.2x+0.010.x-(0.9)=0

We add all the numbers together, and all the variables

x^2-0.9=0

a = 1; b = 0; c = -0.9;
Δ = b2-4ac
Δ = 02-4·1·(-0.9)
Δ = 3.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.6}}{2*1}=\frac{0-\sqrt{3.6}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.6}}{2*1}=\frac{0+\sqrt{3.6}}{2}
=\frac{\sqrt{}}{2}
$